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-5v^2+41v-42=0
a = -5; b = 41; c = -42;
Δ = b2-4ac
Δ = 412-4·(-5)·(-42)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-29}{2*-5}=\frac{-70}{-10} =+7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+29}{2*-5}=\frac{-12}{-10} =1+1/5 $
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